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Two identical conducting rods are first connected independently to two vassels, one containing water at 100degree and other containing ice at 0degree. In the second case, the rods are joined end to end and connected to the same vessels. Let q1 and q2 be the rate of melting of ice in two cases respectively. Find the ratio q1/q2.

Amit Saxena , 12 Years ago
Grade upto college level
anser 1 Answers
Askiitians Tutor Team

To tackle this problem, we need to analyze the heat transfer through the conducting rods in both scenarios. The key here lies in understanding how heat flows from the hot water to the ice and how the configuration of the rods affects this flow.

Understanding Heat Transfer

Heat transfer occurs through conduction, which is governed by Fourier's law. The rate of heat transfer (Q) through a conductor is given by the formula:

Q = k * A * (T_hot - T_cold) / L

Where:

  • Q = rate of heat transfer
  • k = thermal conductivity of the material
  • A = cross-sectional area of the rod
  • T_hot = temperature of the hot side (water)
  • T_cold = temperature of the cold side (ice)
  • L = length of the rod

First Case: Independent Connection

In the first scenario, each rod is connected independently to the hot and cold vessels. Let's denote the heat transfer through each rod as Q1. The temperatures are:

  • Hot side (water): 100°C
  • Cold side (ice): 0°C

Using the formula, we can express the rate of heat transfer for each rod:

Q1 = k * A * (100 - 0) / L = k * A * 100 / L

This heat transfer will cause the ice to melt, and the rate of melting of ice (q1) will be proportional to the heat transferred, so:

q1 ∝ Q1

Second Case: End-to-End Connection

In the second scenario, the rods are connected end to end, effectively doubling the length of the conductor. The new length (L') is now 2L. The heat transfer in this case (Q2) can be expressed as:

Q2 = k * A * (100 - 0) / (2L) = (k * A * 100) / (2L)

Thus, the rate of heat transfer in this configuration is halved:

Q2 = Q1 / 2

As before, the rate of melting of ice (q2) will be proportional to the heat transferred:

q2 ∝ Q2

Finding the Ratio of Melting Rates

Now we can find the ratio of the rates of melting of ice in the two cases:

q1/q2 = Q1 / Q2 = Q1 / (Q1 / 2) = 2

Final Thoughts

The ratio of the rates of melting of ice in the two cases is:

q1/q2 = 2

This means that in the first case, where the rods are connected independently, the rate of melting of ice is twice as much as in the second case, where the rods are connected end to end. This illustrates how the configuration of conductors can significantly impact heat transfer and, consequently, the rate of phase change in materials like ice.

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