Arun
Last Activity: 7 Years ago
Dear Vaibhav
Mass of water = 1 gm = .001 kg
Volume of water = mass/density = .001/1000=.000001 m³
= 1 cm³
Change in volume = 1650 -1 = 1649 cm³
dQ = m*L = 540 * 4.2 * 10^7 erg.
P = 1 atm = 76* 13.6 *9.8
dU = dQ - P* dV
= 22.68 * 10^9 - 1.67 * 10^9
= 21.01 * 10^9 erg
Regards
Arun(askIITians forum expert)