Flag Thermal Physics> The volume of steam produced by 1g of wat...
question mark

The volume of steam produced by 1g of water at 100°c is 1650 cm3.Calculate the change in internal energy during the change of state givenJ = 4.2 × 107 erg cal–1 g = 98 J cm/s2latent heat of steam = 540 cal/g

Vaibhav shukla , 7 Years ago
Grade 11
anser 3 Answers
Arun

Last Activity: 7 Years ago

Dear Vaibhav
 
Mass of water = 1 gm = .001 kg
Volume of water = mass/density = .001/1000=.000001 m³
= 1 cm³
Change in volume = 1650 -1 = 1649 cm³
dQ = m*L = 540 * 4.2 * 10^7 erg.
P = 1 atm = 76* 13.6 *9.8
dU = dQ - P* dV
 = 22.68 * 10^9 - 1.67 * 10^9
 = 21.01 * 10^9  erg
 
Regards
Arun(askIITians forum expert)
 

ankit singh

Last Activity: 4 Years ago

From first law of thermodynamics, 

δQ=dU+δW
54×4.184=dU+PdV
54×4.184=dU+1.013×105×167.1×1060
On solving, we will get dU=208.7J

Ravindra Nagalapura

Last Activity: 2 Years ago

Not correct , initial value of steam = 0, since there is no state change happened as yet.
so change in volume = (1650 – 0) = 1650 cm3

star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments