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The volume of steam produced by 1g of water at 100°c is 1650 cm3.Calculate the change in internal energy during the change of state givenJ = 4.2 × 107 erg cal–1 g = 98 J cm/s2latent heat of steam = 540 cal/g
Dear Vaibhav Mass of water = 1 gm = .001 kg Volume of water = mass/density = .001/1000=.000001 m³ = 1 cm³ Change in volume = 1650 -1 = 1649 cm³ dQ = m*L = 540 * 4.2 * 10^7 erg. P = 1 atm = 76* 13.6 *9.8 dU = dQ - P* dV = 22.68 * 10^9 - 1.67 * 10^9 = 21.01 * 10^9 erg Regards Arun(askIITians forum expert)
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