The specific heats of the gas are Cp=0.2cal/gm°C and Cv=0.15cal/gm°C find a) the molar mass of the gas b) the number of degree of freedom of the gas molecules [ Take R=2cal/mol.°C]

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Arun · Answer

Dear Hemant As we know. Cp – Cv = n* R 0.2 – 0.15 = n * 0.0821 0.05/0.0821 = n n = 0.61 moles Regards Arun

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HETAV PATEL

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The specific heats of the gas are Cp=0.2cal/gm°C and Cv=0.15cal/gm°C find a) the molar mass of the gas b) the number of degree of freedom of the gas molecules [ Take R=2cal/mol.°C]

The specific heats of the gas are Cp=0.2cal/gm°C and Cv=0.15cal/gm°C find
a) the molar mass of the gas
b) the number of degree of freedom of the gas molecules [ Take R=2cal/mol.°C]

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The specific heats of the gas are Cp=0.2cal/gm°C and Cv=0.15cal/gm°C find a) the molar mass of the gas b) the number of degree of freedom of the gas molecules [ Take R=2cal/mol.°C]

The specific heats of the gas are Cp=0.2cal/gm°C and Cv=0.15cal/gm°C find a) the molar mass of the gasb) the number of degree of freedom of the gas molecules [ Take R=2cal/mol.°C]

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The specific heats of the gas are Cp=0.2cal/gm°C and Cv=0.15cal/gm°C find
a) the molar mass of the gas
b) the number of degree of freedom of the gas molecules [ Take R=2cal/mol.°C]