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the following pics are taken from resnick halliday fundamentals of physics.
They clearly say that the entropy change of the system for an irreversible process between two equilibrium states i and f (say) will be same as that for a reversible process between the same two states.This is because entropy being state function depends only on the initial and final states...and for convenience we write it as equal to that for the reversible process..as
dSsystem = [i ][f ] (dQr / T)........where dQr is the heat taken by the system in the reversible process.
Now they again say that total entropy change of system and surrounding for a reversible process will be zero and that for an irreversible process will be greater than zero.
The first part is clear...
if in a reversible process system absorbs heat dQr ,then surrounding also loses the same heat .
So dSsurrounding for reversible process = - [i ][f ] (dQr / T)
So dSuniverse(reversible process)
= dSsystem+ dSsurrounding = [i ][f ] (dQr / T) - [i ][f ] (dQr / T) = 0
Now how should i define dSsurrounding(for irreversible process) such that
dSuniverse(irreversible process) = dSsystem+ dSsurrounding > 0
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It is to be noted that dSsystem = [i ][f ] (dQr / T) for both reversible and irreversible
process as entropy of the system is a state function and does not depend on
the path followed (read the passages)
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Kevin Nash , 12 Years ago
Grade upto college level
anser 1 Answers
Askiitians Tutor Team

Let's break down the concepts of entropy change in reversible and irreversible processes, focusing on how to define the change in the surroundings for an irreversible process. This will help clarify why the total entropy change for the universe is greater than zero in such cases.

Understanding Entropy as a State Function

Entropy is indeed a state function, which means that its change depends only on the initial and final states of a system, not on the path taken to get from one to the other. In your example, the change in entropy for the system, denoted as dSsystem, can be expressed as:

  • dSsystem = ∫if (dQr / T)

This equation holds true for both reversible and irreversible processes when transitioning between the same initial (i) and final (f) states.

Entropy Change in Reversible Processes

For a reversible process, the surroundings experience an equal and opposite change in entropy. If the system absorbs heat dQr, the surroundings lose the same amount of heat, leading to:

  • dSsurrounding = - ∫if (dQr / T)

Consequently, the total change in entropy for the universe (system plus surroundings) in a reversible process is:

  • dSuniverse = dSsystem + dSsurrounding = 0

Entropy Change in Irreversible Processes

In contrast, for an irreversible process, the situation is different. While the change in entropy of the system remains the same, the surroundings do not lose heat in a manner that perfectly balances the system's gain. Instead, we need to consider the heat exchange in a way that reflects the irreversibility of the process.

Defining dSsurrounding for Irreversible Processes

For an irreversible process, the heat exchange with the surroundings can be defined as:

  • dSsurrounding = - ∫if (dQirr / T)

Here, dQirr represents the heat exchanged in the irreversible process, which is typically greater than dQr due to the inefficiencies and additional entropy produced. This leads to:

  • dSuniverse = dSsystem + dSsurrounding > 0

Why is dSuniverse Greater Than Zero?

The key point here is that in an irreversible process, the entropy produced within the system and surroundings results in a net increase in the total entropy of the universe. This is a reflection of the second law of thermodynamics, which states that the total entropy of an isolated system can never decrease over time.

Example to Illustrate

Consider a hot cup of coffee placed in a cooler room. If the coffee cools down (an irreversible process), it loses heat to the surroundings, but the heat lost is not fully reversible. The surroundings gain some entropy due to the heat absorbed, but the process also generates additional entropy due to the spontaneous nature of heat flow from hot to cold. Thus, the total entropy change is positive.

In summary, while the entropy change of the system remains the same for both reversible and irreversible processes, the way we define the entropy change of the surroundings differs significantly, leading to a net increase in the total entropy of the universe for irreversible processes. This distinction is crucial in understanding the fundamental principles of thermodynamics.

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