badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

The equation of state of a gas is PV=nRT(1-B/V),where R is the constant and B is a function of temperature alone.show that the workdone by one mole of this gas during a quasi static isothermal expansion from initial volume Vi to Vf.

9 months ago

Answers : (2)

Saurabh Koranglekar
askIITians Faculty
10233 Points
8 months ago
Vikas TU
13783 Points
							
Dear student
W = 2.3026 RT log10 (V2/V1)
According to first law of thermodynamics, heat used up for the expansion of gas = W/J
So, H = 2.3026 (RT/J) log10 (V2/V1)
Since P1V1 = P2V2, thus, V2/V1= P1/P2
Substituting forV2/V1, H = 2.3026 (RT/J) log10 (P1/P2)
On the other hand, if the gas is compressed, the work is done on the gas and is therefore negative. The work done for isothermal compression is given by,
W = -2.3026 RT log10 (V2/V1)
So, W =2.3026 RT log10 (V1/V2)
Therefore, H = 2.3026 (RT/J) log10 (V1/V2)
and H = 2.3026 (RT/J) log10 (P2/P1)
Good Luck 
 
8 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details