Sir i have doubt in topmost question can you please give me the solution now

We have a pulley with mass ‘m’ on one side and mass ‘m/2’ on the other side.The acceleration of the system, a = Net pulling force/Total massa = [mg-(mg/2)] / [m+(m/2)] = g/3Change in pressure, Δp = ρgehΔp = 103 * (g-(g/3)) * 0.15 = 103 * (2g/3) * 0.15Δp = 103 * ((2*10)/3) * 0.15 = 103 Nm-2 = 1kPaAns: Option B

Approved