Flag Thermal Physics> pls see to following problem and give hin...
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pls see to following problem and give hints how to tackle it.
a container of volume v0 contain ideal gas at pressure p0.the gas is pumped out from container at rate dv/dt=r. pressure of gas taken out equals pressure inside the container. find pressure of gas as function of time.

Hrishant Goswami , 12 Years ago
Grade 10
anser 1 Answers
Askiitians Tutor Team

To tackle this problem, we need to understand the relationship between the volume of gas in the container, the pressure, and how they change over time as gas is pumped out. We can use the ideal gas law, which states that for an ideal gas, the product of pressure (P) and volume (V) is proportional to the number of moles (n) and the temperature (T). In our case, we can simplify this since the temperature is constant and the number of moles will change as we pump out the gas.

Setting Up the Problem

Initially, we have a container with volume V0 and pressure P0. As gas is pumped out at a rate of dv/dt = r, the volume of gas remaining in the container at any time t can be expressed as:

  • V(t) = V0 - rt

Here, V(t) represents the volume of gas left in the container after time t.

Applying the Ideal Gas Law

According to the ideal gas law, we can express the pressure inside the container as:

  • P(t) * V(t) = nRT

Since the number of moles n is proportional to the volume of gas remaining, we can rewrite this as:

  • P(t) * (V0 - rt) = P0 * V0

Here, P0 * V0 represents the initial state of the gas when the container was full.

Deriving the Pressure Function

Now, we can solve for P(t):

  • P(t) = (P0 * V0) / (V0 - rt)

This equation gives us the pressure of the gas as a function of time. It shows that as we pump out gas (increasing t), the volume V(t) decreases, leading to an increase in pressure P(t) as long as V0 - rt remains positive.

Understanding the Behavior Over Time

As time progresses, if we keep pumping gas out, the volume will eventually reach zero when t = V0/r. At this point, the pressure would theoretically approach infinity, which is a limitation of the ideal gas law under these conditions. In practical terms, this means that the pressure will rise significantly as the volume decreases, until the gas is fully evacuated.

Final Thoughts

In summary, the pressure of the gas in the container as a function of time can be expressed as:

  • P(t) = (P0 * V0) / (V0 - rt)

This relationship highlights how the pressure changes inversely with the volume of gas remaining in the container. Keep in mind that this model assumes ideal behavior and constant temperature throughout the process.

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