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It is proposed to build refrigeration plant for a cold storage to be maintained at -3°C. The ambient temperature is 27°C. If 5×10 6 kJ/h of energy is to be continuously removed from the cold storage, the minimum power required to run the refrigerator will be 14.3Kw 75.3 kW 154.3 kW 245.3 kW It is proposed to build refrigeration plant for a cold storage to be maintained at -3°C. The ambient temperature is 27°C. If 5×106 kJ/h of energy is to be continuously removed from the cold storage, the minimum power required to run the refrigerator will be14.3Kw75.3 kW154.3 kW 245.3 kW
I hope you know the relation(Q1/T1)=(Q2/T2)where Q1 =heat rejected in hot reservoir=5×106kJT1 =temperature of hot reservoir=(27+273)K=300K Q2 =heat absorbed from cold reservoirT2=temperature of cold reservoir=(-3+273)=300KUssing the relation and putting the valuesQ2 =5.55×106 kJWork input=Q1-Q2=0.55 ×106kJPower=0.55kJ/h=(0.55×106)/(60×60) kJ/s=154.3kJ/s=154.3 kW
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