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Grade: 11
        In an isobaric process, the change in temperature for 0.1 mole of N2 is 300K. The work done by the gas is
5 months ago

Answers : (1)

Arun
11541 Points
							
Dear Piyush
 
In an isobaric process-
Work done = p * \DeltaV
= n *R* \DeltaT
Please put all the values and get the answer.
 
Regards
Arun (askIITians forum expert)
5 months ago
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