# In an isobaric process, the change in temperature for 0.1 mole of N2 is 300K. The work done by the gas is

Grade:11

## 1 Answers

Arun
25757 Points
5 years ago
Dear Piyush

In an isobaric process-
Work done = p * $\Delta$V
= n *R* $\Delta$T
Please put all the values and get the answer.

Regards
Arun (askIITians forum expert)