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In an isobaric process, the change in temperature for 0.1 mole of N2 is 300K. The work done by the gas is

In an isobaric process, the change in temperature for 0.1 mole of N2 is 300K. The work done by the gas is

Grade:11

1 Answers

Arun
25763 Points
3 years ago
Dear Piyush
 
In an isobaric process-
Work done = p * \DeltaV
= n *R* \DeltaT
Please put all the values and get the answer.
 
Regards
Arun (askIITians forum expert)

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