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In an isobaric process, the change in temperature for 0.1 mole of N2 is 300K. The work done by the gas is

Piyush Upadhyay , 7 Years ago
Grade 11
anser 1 Answers
Arun
Dear Piyush
 
In an isobaric process-
Work done = p * \DeltaV
= n *R* \DeltaT
Please put all the values and get the answer.
 
Regards
Arun (askIITians forum expert)
Last Activity: 7 Years ago
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