In an isobaric process, the change in temperature for 0.1 mole of N2 is 300K. The work done by the gas is

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Arun · Answer

Dear Piyush In an isobaric process- Work done = p * V = n *R* T Please put all the values and get the answer. Regards Arun (askIITians forum expert)

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In an isobaric process, the change in temperature for 0.1 mole of N2 is 300K. The work done by the gas is

In an isobaric process, the change in temperature for 0.1 mole of N2 is 300K. The work done by the gas is

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In an isobaric process, the change in temperature for 0.1 mole of N2 is 300K. The work done by the gas is

In an isobaric process, the change in temperature for 0.1 mole of N2 is 300K. The work done by the gas is

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