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if work is done on the gas then is released or absorbed by the gas..? $u=0 given

if work is done on the gas then is released or absorbed by the gas..?
$u=0 given

Grade:12

1 Answers

Vasantha Kumari
askIITians Faculty 38 Points
7 years ago
We know that according to first law of thermodynamics,
dQ = dU + dW
When work is done by the gas, it expands and dW is taken to be positive (dW = +ve)
When work is done on the gas, it compresses and dW is taken to be negative(dW = –ve)

Thanks & Regards,

Vasantha Sivaraj,

askIITians faculty

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