Flag Thermal Physics> IF CP-CV = 1.00 R FOR A GAS IN ONE STATE ...
question mark

IF CP-CV = 1.00 R FOR A GAS IN ONE STATE AND IS CP-CV = 1.08 R IN THE SECOND CASE .LET PA,PB DENOTE RESPECTIVE PRESSURES IN TWO STATES WHILE TA,TB THE TEMPRATURES IN THE TWO STATES THEN:



  1. PA < PB AND TA, >TB

  2. PA >PB AND TA,< TB

  3. PA = PB AND TA, B



    • PA > PB AND TA,= TB


Shane Macguire , 12 Years ago
Grade upto college level
anser 1 Answers
Askiitians Tutor Team

To analyze the relationship between pressure and temperature in the two states of a gas, given the specific heat differences, we can use the equations of state for ideal gases along with the definitions of specific heats at constant pressure (CP) and constant volume (CV). The equations you provided indicate that the difference between CP and CV is different in two states, which suggests that the gas behaves differently under varying conditions.

Understanding the Specific Heats

The specific heats of a gas are defined as follows:

  • CP is the heat capacity at constant pressure.
  • CV is the heat capacity at constant volume.

The difference between these two values, CP - CV, is related to the gas constant (R) and the degrees of freedom of the gas molecules. For an ideal gas, this difference is typically equal to R for monatomic gases, and it can be greater for polyatomic gases.

Analyzing the Given Conditions

In your scenario, we have:

  • For state 1: CP - CV = 1.00 R
  • For state 2: CP - CV = 1.08 R

This indicates that the gas in the second state has a higher heat capacity difference, suggesting that it might be a more complex gas or under different conditions (like higher temperature or pressure). Now, let’s consider the implications of these differences on pressure and temperature.

Applying the Ideal Gas Law

The ideal gas law states:

P V = n R T

Where:

  • P = pressure
  • V = volume
  • n = number of moles
  • R = ideal gas constant
  • T = temperature

From this equation, we can see that if the volume (V) and the number of moles (n) are constant, any change in temperature (T) will directly affect the pressure (P). Thus, if we know the relationship between the specific heats and the states of the gas, we can infer the relationship between pressure and temperature.

Evaluating the Options

Now, let’s evaluate the provided options based on the information we have:

  • PA < PB and TA > TB
  • PA > PB and TA < TB
  • PA = PB and TA < TB
  • PA > PB and TA = TB

Given that CP - CV is greater in the second state, it implies that for a given increase in temperature, the pressure must also increase to maintain the relationship dictated by the ideal gas law. Therefore, if TA is greater than TB, it suggests that PA should also be greater than PB to satisfy the conditions of the gas laws.

Conclusion

Based on this analysis, the most logical conclusion is:

PA > PB and TA < TB

This means that in the first state, the gas has a higher pressure but a lower temperature compared to the second state, which aligns with the changes in specific heats and the behavior of ideal gases under varying conditions.

ApprovedApproved
Last Activity: 10 Months ago
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments