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Grade: 11

                        

. Find the average momentum of molecules of hydrogen gas in a container at temperature 300 K.

2 years ago

Answers : (2)

SAHIL PRASAD
30 Points
							We know, formula of average Kinetic energy of a molecule of gas at Temperature T is K.E = 3/2kT where , k is boltzmann constant { k = universal gas constant / Avogadro`s constant = 1.38 × 10^-23 } T is the temperature .also we know, relation between momentum and kinetic energy is P² = 2(K.E)mwhere P is the momentum , m is the mass now, for above explanation we can get, average momentum of Hydrogen molecule is P_{av} = \sqrt{2\times\:KE\times\:m}P_{av} = \sqrt{2\times\:KE\times\:m} \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  =  \sqrt{2 \times  \frac{3}{2}kT \times m} \\  \\ \:  \:  \:  \:  \:  \:  \:  \:  \:     =  \sqrt{3kTm} here , K = 1.38 × 10^-23 T = 300K and , m = molecular mass/Avogadro`s number = 2 × 10^-3/6.023 × 10^23 Kgso, Pav = √{3 × 1.38 × 10^-23 × 300 × 2 × 10^-3/6.023 × 10^23 }= √{ 412.41 × 10^-49}= √{41.241} × 10^-24 Kg.m/s = 6.42 × 10^-24 kg.m/s hence, average momentum of Hydrogen molecule is 6.42 × 10^-24 kg.m/s
						
2 years ago
Kundan Kr
9 Points
							
P av = M*V av
And we know that average velocity of gas molecules in any container is always zero as particles are moving randomly in all direction.
So av momentum is zero
one year ago
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