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Grade 11Thermal Physics

equal amount of an Ideal diatomic gas is taken in two cylinders a and b at 300K. The Piston of A is free to move while that of B is it fixed. Same quantity of heat is given to both the cylinders. If the rise in temperature of gas is a is 30 k, the rise in temperature of gas in B is
In this solution how to calculate Cp/Cv

Profile image of Sudhanva G V
7 Years agoGrade 11
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1 Answer

Profile image of Forum 1
3 Years ago
Hello Student

Solution:
Process in cylinder A is constant pressure process.
Process in cylinder B is constant volume process.
Heat supplied is :
Q=nCp​ΔT1​
Q=nCv​ΔT2​
Cp/Cv​​​=​ΔT2/ΔT1​​=γ
For a monoatomic gas is
γ=7/5
HenceT2​=7/5​×30=42K

Hope this solution is helpful.