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Calculate the internal energy of 1 mole of an ideal gas at 250ºC.
To find out the internal energy of the ideal gas, substitute 1 mole for n, 250̊ C for temperature T and 8.31 J/ mol. K for the gas constant R in the equation E = 3/2 nRT,E = 3/2 nRT = 3/2 (1 mol) (8.31 J/ mol. K) (250̊ C) = (1.5)( 1 mol) (8.31 J/ mol. K) (250+273) K = (1.5)( 1 mol) (8.31 J/ mol. K) (523) K= 6519.195 JRounding off to three significant figures, the internal energy of the ideal gas will be 6520 J.
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