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Calculate the fall in temperature when a gas initially at 72°C is expandedsuddenly to eight times its original volume. ( = 5/3)
Dear Vaibhav T1 * V1(gamma-1) = T2* V2(gamma-1) T2 = T1 (V1/V2)(gamma-1) T2 = 345 *(x/8x)(5/3 -1) on solving T2 = 345 * (1/4) = 86.25 K Regards Arun (askIITians forum expert)
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