MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: upto college level
        
An ideal undergoes a reversible isothermal expansion at 132ºC. The entropy of the gas increase by 46.2 J/K. How much heat is absorbed?
3 years ago

Answers : (1)

Deepak Patra
askIITians Faculty
471 Points
							To obtain the absorbed heat Q, substitute 46.2 J/K for ΔS and 132̊ C for T in the equation Q = (ΔS) (T),
Q = (ΔS) (T)
= (46.2 J/K) (132̊ C)
= (46.2 J/K) ((132 +273) K)
= (46.2 J/K) (405 K)
= 1.87×104 J
From the above observation we conclude that, the absorbed heat Q will be 1.87×104 J.

3 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Get Extra Rs. 551 off

COUPON CODE: SELF20


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Get Extra Rs. 594 off

COUPON CODE: SELF20

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details