Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

(a) Use the data in Exercise 1 to calculate the rate at which heat lows out through the surface of the Earth. (b) Suppose that this heat flux is due to the presence of a hot core in the Earth and that this core has a radius of 3470 km. Assume also that the material lying between the core and the surface of the Earth contains no sources of heat and has an average thermal conductivity of 4.2 W/m . K. Use the result of problem 3 to calculate the temperature of the core. (Assume that the Earth’s surface is at 0ºC.) the answer obtained is too high by a factor of about 10. Why?

(a) Use the data in Exercise 1 to calculate the rate at which heat lows out through the surface of the Earth. (b) Suppose that this heat flux is due to the presence of a hot core in the Earth and that this core has a radius of 3470 km. Assume also that the material lying between the core and the surface of the Earth contains no sources of heat and has an average thermal conductivity of 4.2 W/m . K. Use the result of problem 3 to calculate the temperature of the core. (Assume that the Earth’s surface is at 0ºC.) the answer obtained is too high by a factor of about 10. Why?

Grade:upto college level

1 Answers

Deepak Patra
askIITians Faculty 471 Points
6 years ago
(a)
As the surface area of earth is 4πr2 and the average rate at which heat flows out through the surface of the Earth in North America is 54 mW/m2, thus the rate H at which heat flows out through the surface of Earth will be, 233-1252_1.PNG
233-1656_1.PNG

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free