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Grade 11Thermal Physics

a metal rod A of 25 cm length expands by 0.050 cm when its temperature is rasied from 0 deg to 100 deg. another rod B of a different metal of length 40 cm expands by 0.040 cm for the same rise in temp. A third rod C of 50 cm length is made up of pieces of rods A and B placed end to end expands by 0.03 cm on heating from 0 deg to 50 deg. Find the lengths of each portion of the composite rod.

Profile image of Radhika Batra
12 Years agoGrade 11
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1 Answer

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ApprovedApproved Tutor Answer1 Year ago

To solve this problem, we need to understand how thermal expansion works in different materials. The expansion of a rod when heated can be described using the formula:

Understanding Thermal Expansion

The linear expansion of a material can be expressed as:

ΔL = L₀ * α * ΔT

Where:

  • ΔL = change in length
  • L₀ = original length of the rod
  • α = coefficient of linear expansion of the material
  • ΔT = change in temperature

From the problem, we have two rods, A and B, with known expansions when heated from 0°C to 100°C. We can use this information to find the coefficients of linear expansion for each rod.

Calculating Coefficients of Linear Expansion

For rod A:

  • Original length (L₀) = 25 cm
  • Change in length (ΔL) = 0.050 cm
  • Change in temperature (ΔT) = 100°C

Using the formula:

0.050 = 25 * αA * 100

Solving for αA gives:

αA = 0.050 / (25 * 100) = 0.00002 cm/cm/°C

For rod B:

  • Original length (L₀) = 40 cm
  • Change in length (ΔL) = 0.040 cm
  • Change in temperature (ΔT) = 100°C

Using the same formula:

0.040 = 40 * αB * 100

Solving for αB gives:

αB = 0.040 / (40 * 100) = 0.00001 cm/cm/°C

Analyzing the Composite Rod C

Now, we have a composite rod C made up of pieces of rods A and B. The total length of rod C is 50 cm, and it expands by 0.03 cm when heated from 0°C to 50°C. We can denote the lengths of the portions of rods A and B in rod C as x and y, respectively.

Since the total length of rod C is 50 cm, we have:

x + y = 50

Now, the change in length for rod C can be expressed as:

ΔLC = ΔLA + ΔLB

For rod A in C:

ΔLA = x * αA * ΔT

For rod B in C:

ΔLB = y * αB * ΔT

Substituting the values for ΔT (50°C) and the coefficients:

0.03 = (x * 0.00002 * 50) + (y * 0.00001 * 50)

This simplifies to:

0.03 = 0.001 * x + 0.0005 * y

Setting Up the Equations

Now we have two equations:

  • 1. x + y = 50
  • 2. 0.001x + 0.0005y = 0.03

We can solve these equations simultaneously. From the first equation, we can express y in terms of x:

y = 50 - x

Substituting this into the second equation:

0.001x + 0.0005(50 - x) = 0.03

0.001x + 0.025 - 0.0005x = 0.03

0.0005x = 0.03 - 0.025

0.0005x = 0.005

x = 0.005 / 0.0005 = 10 cm

Now substituting back to find y:

y = 50 - 10 = 40 cm

Final Results

The lengths of each portion of the composite rod C are:

  • Length of rod A in C: 10 cm
  • Length of rod B in C: 40 cm

This analysis shows how different materials expand differently and how we can use their properties to solve composite problems effectively.