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A carnot engine takes 300 calories heat from a source at 500K and rejects 150 caloies of heat to the sink,find the temperature of the sink

christopher , 7 Years ago
Grade 11
anser 3 Answers
Samanvitha
In carnot engine Q1/Q2=T1/T2 HERE Q1 is 300 K Q2 IS 150K AND T1 IS 500K BY APPLYING THE FORMULA T2 IS 250 K
ApprovedApproved
Last Activity: 7 Years ago
Varon
Hi christopher
apply this formula
Q1/T1 = Q2/T2
300/500 = 150/X
SO x = 250
thats it
thank you very much
ApprovedApproved
Last Activity: 7 Years ago
Rishi Sharma
Dear Student,
Please find below the solution to your problem.

In carnot engine Q1/Q2=T1/T2
HERE Q1 is 300 K Q2 IS 150K AND T1 IS 500K
BY APPLYING THE FORMULA
T2 IS 250 K

Thanks and Regards
Last Activity: 5 Years ago
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