Navjyot Kalra
Last Activity: 11 Years ago
Sol. v = 100 cc
∆θ = °C
T = 5 min
For water
mS∆θ/dt = KA/l ∆θ
⇒ 100 * 10^-3 * 1000 * 4200/5 = KA/l
For Kerosene
Ms/at = KA/l
⇒ 100 * 10^-3 * 800 * 2100/t = KA/l
⇒ 100 * 10^-3 * 800 * 2100/t = 100 * 10^-3 * 1000 * 4200/5
⇒ T = 5 * 800 * 2100/1000 * 4200 = 2 min