5) A small pond of depth 0.5 m deep is exposed to a cold winter with outside temperature of
263 K. Thermal conductivity of ice is K = 2.2 Wm-1K-1, latent heat L = 3.4 × 105 Jkg-1 and
density ρ = 0.9 × 103 kgm-3. Take thestep by step please
5) A small pond of depth 0.5 m deep is exposed to a cold winter with outside temperature of
263 K. Thermal conductivity of ice is K = 2.2 Wm-1K-1, latent heat L = 3.4 × 105 Jkg-1 and
density ρ = 0.9 × 103 kgm-3. Take the
263 K. Thermal conductivity of ice is K = 2.2 Wm-1K-1, latent heat L = 3.4 × 105 Jkg-1 and
density ρ = 0.9 × 103 kgm-3. Take the
step by step please
ankur , 7 Years ago
Grade 12
