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300g of water at 25 ○ C is added to 100g 0f ice at 0 ○ C. The final temperature of mixture is -5/2 ○ C -5/3 ○ C -5 ○ C 0 ○ C The answer is 0 ○ but I got -5/4 using Q1 + Q2=Q3 formula PLEASE HELP!!!!

300g of water at 25○C is added to 100g 0f ice at 0○C. The final temperature of mixture is 
  1. -5/2○C
  2. -5/3○C
  3. -5○C
  4. 0○C
The answer is 0○ but I got -5/4 using Q1 + Q2=Q3 formula PLEASE HELP!!!!

Grade:12th pass

3 Answers

Rinki jain
12 Points
6 years ago
1 st find heat content of water by Q=mst And latent heat req. To melt ice by Q=ml ... U will see that water is not able to melt the entire ice.... Therefore some ice will remain and temp. Will be 0 Degree Celsius
Yash Chourasiya
askIITians Faculty 256 Points
3 years ago
Dear Student

The heat required for 100g of ice at 0∘C to change into
Water at0∘C = mL = 100×80×4.2 = 33,600J…(i)
The heat released by 300g of water at 25∘C to change its
temperature to 0∘C = mcΔT = 300×4.2×25 = 31,500J….(ii)
Since the energy in eq.(ii) is less than of eq(i)
therefore the final temperature will be 0∘C

I hope this answer will help you.
Thanks & Regards
Yash Chourasiya
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13 Points
2 years ago
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