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22320 cal of heat is supplied to 100g of ice at 0 degree C. If the latent heat of fusion of ice is 80cal/g and latent heat of vapourisation of water is 540 cal/g, the final amount of water thus obtained and its temperature respectively are 1) 8g, 100degree C 2) 100g, 90degree C 3) 92g, 100degree C 4) 80g, 100degree C

22320 cal of heat is supplied to 100g of ice at 0 degree C. If the latent heat of fusion of ice is 80cal/g and latent heat of vapourisation of water is 540 cal/g, the final amount of water thus obtained and its temperature respectively are
1) 8g, 100degree C
2) 100g, 90degree C
3) 92g, 100degree C
4) 80g, 100degree C

Grade:12th pass

1 Answers

Soumyadeep Datta
33 Points
2 years ago
Answer would be option C
The ice would take 8000cal to turn into water by formula   mass×80
Then the water would take 10000 cal   by formula mass× c × change in temp(which is 100) 
So remaining 4320cal would turn 8g of water into vapour

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