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22320 cal of heat is supplied to 100g of ice at 0 degree C. If the latent heat of fusion of ice is 80cal/g and latent heat of vapourisation of water is 540 cal/g, the final amount of water thus obtained and its temperature respectively are
1) 8g, 100degree C
2) 100g, 90degree C
3) 92g, 100degree C
4) 80g, 100degree C

VIDYARANI SINGADI , 7 Years ago
Grade 12th pass
anser 1 Answers
Soumyadeep Datta
Answer would be option C
The ice would take 8000cal to turn into water by formula   mass×80
Then the water would take 10000 cal   by formula mass× c × change in temp(which is 100) 
So remaining 4320cal would turn 8g of water into vapour
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Last Activity: 7 Years ago
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