2 bodies A and B has thermal emissivities of 0.01 and 0.81 respectively . The outer surface areas of both bodies are same . Both body emits total radiant power at same rate .The wavelenth of B corresponding to maximum spectral radiancy in radiation from B shifted from wavelength corresponding to maximum spectral radiancy in radiation from A by 1 micrometre . If temperature of A is 5802 K , then find the wavelength of B .

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Vikas TU · Answer

Let Ta and Tb be the the temp. of A and B. ten, Ta = 3Tb.................(1) And use formulae: Ka x Ta = Kb x Tb where Ka and Kb are the lamdas for A and B respectively. solve the eqns. and get the values.

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