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Grade: 11

                        

2 bodies A and B has thermal emissivities of 0.01 and 0.81 respectively . The outer surface areas of both bodies are same . Both body emits total radiant power at same rate .The wavelenth of B corresponding to maximum spectral radiancy in radiation from B shifted from wavelength corresponding to maximum spectral radiancy in radiation from A by 1 micrometre . If temperature of A is 5802 K , then find the wavelength of B .

4 years ago

Answers : (1)

Vikas TU
12284 Points
							
Let Ta and Tb be the the temp. of  A and B.
ten,
Ta = 3Tb.................(1)
And use formulae:
Ka x Ta = Kb x Tb
where Ka and Kb are the lamdas for A and B respectively.
solve the eqns.
and get the values.
4 years ago
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