A sealed container with negligible coefficient of volumetric expansion contains helium When it is heated from 300K to 600K the average KE of helium atom is

Dear pallvi

Average K.E of a molecule is given as

K.E =3/2 kT

chenge in K.E  = 3/2 kT₂  - 3/2kT₁

=3/2k (T₂  - T₁)

=3/2 * 1.38 * 10^-23 ( 600 -300)

=6.21 * 10^-21  J

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Badiuddin

The answer its doubled as KE is directly proportional to T . ie. =3/2xKTAs the KE here is directly proprtinal to Temperature a change in temperature will effect change in KE linearly Hope u got ur answer!