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pallavi pradeep bhardwaj Grade: 12

A sealed container with negligible coefficient of volumetric expansion contains helium When it is heated from 300K to 600K the average KE of helium atom is

7 years ago

Answers : (2)

Badiuddin askIITians.ismu Expert
147 Points

Dear pallvi

Average K.E of a molecule is given as

K.E =3/2 kT

chenge in K.E  = 3/2 kT - 3/2kT1

                     =3/2k (T - T1)

                     =3/2 * 1.38 * 10-23 ( 600 -300)

                     =6.21 * 10-21  J

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7 years ago
Abhinav M
11 Points
										The answer its doubled as KE is directly proportional to T . ie.  =3/2xKTAs the KE here is directly proprtinal to Temperature a change in temperature will effect change in KE linearly         Hope u got ur answer!
6 days ago
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