The molecular weight of oxygen and nitrogen are 32 and 28 respectively At 15 degree celcius the presence of 1 gm oxygen be same as that of 1 gm nitrogen in the same bottle at the temperature

Dear pallavi

pressure p=nRT/V

volume is same for both the gases

number of mole for oxygen = 1/32

number of mole for nitrogen = 1/28

given presuure is same

 n1RT1/V1  = n2RT2/V2

 (1/32) R (273+15)/V  =  (1/28) R T /V

  T=28/32 (288)=252 K

   =-21 C

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