Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
The molecular weight of oxygen and nitrogen are 32 and 28 respectively At 15 degree celcius the presence of 1 gm oxygen be same as that of 1 gm nitrogen in the same bottle at the temperature
Dear pallavi
pressure p=nRT/V
volume is same for both the gases
number of mole for oxygen = 1/32
number of mole for nitrogen = 1/28
given presuure is same
n1RT1/V1 = n2RT2/V2
(1/32) R (273+15)/V = (1/28) R T /V
T=28/32 (288)=252 K
=-21 C
Please feel free to post as many doubts on our discussion forum as you can.If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE & AIEEE preparation. All the best. Regards,Askiitians ExpertsBadiuddin
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !