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The molecular weight of oxygen and nitrogen are 32 and 28 respectively At 15 degree celcius the presence of 1 gm oxygen be same as that of 1 gm nitrogen in the same bottle at the temperature
Dear pallavi pressure p=nRT/V volume is same for both the gases number of mole for oxygen = 1/32 number of mole for nitrogen = 1/28 given presuure is same n1RT1/V1 = n2RT2/V2 (1/32) R (273+15)/V = (1/28) R T /V T=28/32 (288)=252 K =-21 C Please feel free to post as many doubts on our discussion forum as you can.If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE & AIEEE preparation. All the best. Regards,Askiitians ExpertsBadiuddin
Dear pallavi
pressure p=nRT/V
volume is same for both the gases
number of mole for oxygen = 1/32
number of mole for nitrogen = 1/28
given presuure is same
n1RT1/V1 = n2RT2/V2
(1/32) R (273+15)/V = (1/28) R T /V
T=28/32 (288)=252 K
=-21 C
Please feel free to post as many doubts on our discussion forum as you can.If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE & AIEEE preparation. All the best. Regards,Askiitians ExpertsBadiuddin
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