Thermal capacity of 40 g of aluminium (s = 0.2 cal /g K) is

(a) 168 joule/°C

(b) 672 joule/°C

(c) 840 joule/°C

(d) 33.6 joule/°C

(d)

Thermal capacity = ms = 40 × 0.2 = 8 Cal/°C

= 4.2 × 8 J = 33.6 joules/°C

Dear Student,
Please find below the solution to your problem.

Thermal capacity = ms = 40 × 0.2
= 8 Cal/°C
= 4.2 × 8 J
= 33.6 joules/°C

Thanks and Regards