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I know adiabatic work=(P2V2-P1V1)/Y-1..where y is gama. W=R(T2-T1)/Y-1 =Cv(T2-T1)....cos R/Y-1=Cv but in brayton cycle adiabatic work is give as W=[Y(P2V2-P1V1)]/Y-1 ie.W=YR(T2-T1)/Y-1 W=Cp(T2-T1) as.... YR/Y-1=Cp How is this possible?

I know adiabatic work=(P2V2-P1V1)/Y-1..where y is gama.


W=R(T2-T1)/Y-1


=Cv(T2-T1)....cos R/Y-1=Cv


but in brayton cycle adiabatic work is give as


W=[Y(P2V2-P1V1)]/Y-1


ie.W=YR(T2-T1)/Y-1


W=Cp(T2-T1) as.... YR/Y-1=Cp


How is this possible?

Grade:12

1 Answers

ankitesh gupta
63 Points
11 years ago

LOOK 

CP - CV =R

CP / CV     = Y                    WHERE Y IS GAMMA 

 

 DIVIDE 1ST EQUATION WITH CV  FROM THERE FIND THE VALUE OF CV   THEN SUBSTITUTE THE VALUE IN ANY OF THE EQUATION AND GET THE VALUE OF CP  WHICH IS 

   YR/Y-1

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