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Grade 12Thermal Physics

I know adiabatic work=(P2V2-P1V1)/Y-1..where y is gama.

W=R(T2-T1)/Y-1

=Cv(T2-T1)....cos R/Y-1=Cv

but in brayton cycle adiabatic work is give as

W=[Y(P2V2-P1V1)]/Y-1

ie.W=YR(T2-T1)/Y-1

W=Cp(T2-T1) as.... YR/Y-1=Cp

How is this possible?

Profile image of Mandeep Shetty
14 Years agoGrade 12
Answers icon

1 Answer

Profile image of ankitesh gupta
13 Years ago

LOOK 

CP - CV =R

CP / CV     = Y                    WHERE Y IS GAMMA 

 

 DIVIDE 1ST EQUATION WITH CV  FROM THERE FIND THE VALUE OF CV   THEN SUBSTITUTE THE VALUE IN ANY OF THE EQUATION AND GET THE VALUE OF CP  WHICH IS 

   YR/Y-1

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