Flag Thermal Physics> How adiabatic work=Cp(T2-T1)...
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I know adiabatic work=(P2V2-P1V1)/Y-1..where y is gama.

W=R(T2-T1)/Y-1

=Cv(T2-T1)....cos R/Y-1=Cv

but in brayton cycle adiabatic work is give as

W=[Y(P2V2-P1V1)]/Y-1

ie.W=YR(T2-T1)/Y-1

W=Cp(T2-T1) as.... YR/Y-1=Cp

How is this possible?

Mandeep Shetty , 12 Years ago
Grade 12
anser 1 Answers
ankitesh gupta

Last Activity: 12 Years ago

LOOK 

CP - CV =R

CP / CV     = Y                    WHERE Y IS GAMMA 

 

 DIVIDE 1ST EQUATION WITH CV  FROM THERE FIND THE VALUE OF CV   THEN SUBSTITUTE THE VALUE IN ANY OF THE EQUATION AND GET THE VALUE OF CP  WHICH IS 

   YR/Y-1

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