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Since the rate of melting of ice is directly proportional to the amount of heat transfered per unit time,
Then calculating the mag. of heat currents set up in the two rod would give u a fair estimate how fast is the rate.
dQ/dt=(KA/L)T where t is the temperature difference b/w the two.
For First rod , dQ1/dt=(K1A1/L1)T
For the second rod, dQ2/dt=(K2A2/L2)T
Since for the second rod , L2=L1/2 , R2= 2R1 === > A2=4A1 , K2= (1/4)K1
Then dQ2/dt=(K18A1/4L1)T = 2(K1A1/L1)T
Since the rate of heat tranfer is 2 times the first. then the rate of melting would be 2 times as the first = 0.2g/s
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