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How much steam at 100°C will just melt 3200 gm of ice at 10°C?
(Specific heat of ice = 0.5 cal/gm°C, Latent heat of steam=540 cal/gm,
latent heat of ice= 80 cal/gm)
let answer=x gm
3200*(80+(10*0.5))=x*540
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