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A refrigerator has to transfer an average of 263 J of heat per second from temperature -10 C to 25 C. Calculate the average power consumed assuming ideal reversible cycle and no other losses.
A refrigerator has to transfer an average of 263 J of heat per second from temperature -10 C to 25 C. Calculate the average power consumed assuming ideal reversible cycle and no other losses.


10 years ago

36 Points
							Dear student,
$\ COP = \frac{T_L}{T_H - T_L}$

=> COP = 263/35 = 7.514 = QH/W
=> W = 263/7.514 = 35 Watts

10 years ago
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### Course Features

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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions