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Grade: 12

                        

100g ice at 0 o C is mixed with 10g steam at 100 o C. Find the final temperature and composition.

3 years ago

Answers : (2)

Rr
11 Points
							
						
2 years ago
Abid
13 Points
							Latent heat of ice =m×l                                   100×80=8000Latent heat of steam =m×l                                     =10×540 L.H of ice is greater than steam Specific heat of steam = mct                                        =10×1×100=10005400+1000=6400 for steamCompositionQ=mlm=q/lm=6400/80m=80100-80=20g of ice 10+80=90g water
						
2 years ago
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