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100g ice at 0oC is mixed with 10g steam at 100oC. Find the final temperature and composition.

Anshika Srivastava , 8 Years ago
Grade 12
anser 1 Answers
Abid

Last Activity: 7 Years ago

Latent heat of ice =m×l 100×80=8000Latent heat of steam =m×l =10×540 L.H of ice is greater than steam Specific heat of steam = mct =10×1×100=10005400+1000=6400 for steamCompositionQ=mlm=q/lm=6400/80m=80100-80=20g of ice 10+80=90g water
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