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```
When a sample of baking soda is strongly ignited in a crucible ,it suffered a loss in weight of 3.1g the mass of baking soda is?
When a sample of baking soda is strongly ignited in a crucible ,it suffered a loss in weight of 3.1g the mass of baking soda is?

```
4 years ago

## Answers : (5)

Vikas TU
14146 Points
```							The reacn. is:    2NaHCO3     ---------->            Na2CO3     +      CO2        +    H2O     => 2* 84 = 168 gm. CO2 and H2O => 44 + 18 => 62 gm.Just divide them we get,=> 168/62 = 8 gm approx. As 3.1 g was Na2CO3 gm.
```
4 years ago
Shravani
25 Points
```							If we divide 168/62 the answer is not 8 its like 2 (approx) and can u answer me the question by seeing again
```
4 years ago
Vikas TU
14146 Points
```							Correction:mass of baking soda => 168 x 3.1 / 62 => 8 gms approx.mutiply 3.1 gm with baking soda mass too.
```
4 years ago
Debanko Kundu
11 Points
```							2NaHCO3 ------>NaCO3 + H2O + CO2mass of NaHCO3 = 2 × 84 =168mass of CO2 +H2O = 62Mass lost = 3.1 Mass of NaHCO3 = 168 × 3.1 / 62 = 8.4
```
3 years ago
Satya boppana
13 Points
```							168 grams = weight of 2 NaHCo3It losses 62 grams on decomposition by producing water and co2168=62?=3.1Ans: 31×84÷31×10= 8.4 grams
```
one year ago
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