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The ground state energy of hydrogen atom is -13.6 eV. The energy of second excited state of He +ions is eV is

The ground state energy of hydrogen atom is -13.6 eV. The energy of second excited state of He +ions is eV is

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Grade:11

1 Answers

FATHIMA NASREEN K
13 Points
2 months ago
We know that E=-13.6*z^2/n^2
Here z=2 and n=3 
Therefore 
On substituting the equation ,
-13.6*2^2/3^2
=-6.04 ev

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