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`        What is the molarity of h2so4 solution that has a density of 1.84 g/cc and contains 98% by mass of h2so4?(atomic mass of s=32)? Ans=18.4M How? `
4 years ago

Ashutosh Sharma
181 Points
```							Molar mass of H2SO4 = 98g/mol = MmD =density = 1.84g/ccW/w = 98%V = 1dm3 = 1L = 1000ml = 1000ccMass of solution = V x DM = 1000 x 1.84 = 1840g per 1000ccUsing w/w, 98% of 1840g = H2SO4= (98/100) x 1840 = 1803.2g = mNos of moles = m/Mm = 1803.2/98 = 18.4moles per 1000ccThus, molarity = 18.4M (18.4mol/dm3)
```
4 years ago
Swagata
13 Points
```							98% h2so4 by weight means 98g h2so4 in 100g of the solutionGiven density = 1.84g/ccDensity of solution = mass of solution /volume of solution1.84 = 100/ volumeVolume = 100/1.84 = 54.3 mlNo.of moles of h2so4 = weight of h2so4/molar mass of h2so4 = 98/98 = 1 mole Molarity = mole * 1000/54.3 = 18.41M
```
7 months ago
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