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Grade: 12th pass
        
Three solution of strong electrolyte 25ml of .01 M HX , 25ml of 0.1 M h2Y and 50 ml of 0.1 N Z(oh)2 are mixed what is the POH of the solution 
 
one year ago

Answers : (1)

SALETH
14 Points
							
M1V1+M2V2+M3V3=M4V4
0.01x25)+(0.1x25)+(0.05x50) = M4V4
                                                      = 5.25 in 100ml
pH = -log[H+]
      = - log (5.25). = -0.553
pOH = 14 - pH
         = 14 - (-0.553). = 13.44
one year ago
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