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Grade: 12
        
the vapour pressure of benzene at 80 oC is lowered by 10 mm by dissolving 2 g of a non- volatile substance in 78 g of benzene . the vapour pressure o f pure benzene at 80oC is 750 mm .the molecular mass of the substance will be____
 
3 years ago

Answers : (2)

Bhavya
askIITians Faculty
1284 Points
							Dear student
relative lowering of V.P (po-ps/po) = mole fraction of solute
750-740/750 = (2/M)/ 2/M + 78/78
10/750 = (2/M) / 2/M + 1
M = 148
3 years ago
Jms
13 Points
							
po-ps/po=w2/m2 × m1/w1     
750-740/750=2/m2×78/78
   10/750=2/m2
      M2 =150.please uovote it if it is right..(question is from chapter solutions standard 12 )
 
one year ago
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