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Grade upto college level Physical Chemistry

The value of van der Waals’ constant ‘a’ for the gases O2, N2, NH3 and CH4 are 1.360, 1.390, 4.170 and 2.253L2 atm mol-2 respectively. The gas which can most easily be liquefied is a. O2 b. N2 c. NH3 d CH4

Profile image of Amit Saxena
12 Years agoGrade upto college level
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5 Answers

Profile image of Jitender Pal
12 Years ago
Sol. The ease of liquification of a gas depends on their intermolecular force of attraction which in turn is measured in terms of van der Waals’ constant ‘a’. Hence, higher the value of ‘a’, greater the intermolecular force of attraction, easier the liquification. In the present case, NH3 has highest ‘a’, can most easily be liquefied.
Profile image of venkatesh
8 Years ago
ease of liquification is directly proportional to ‘a’.If the value of ‘a’ is more then if we apply even less pressure also the gas can be liquified,so in order to liquify easily we should have more ‘a’. so more ‘a’ =more easily liqification.  
Profile image of Tejovanth
8 Years ago
As NH3 has higher *a value, it can be easily liquifiable. Such that [rate of liquification is directly proportional to a value]
Profile image of Krish Gupta
6 Years ago
Sol. The ease of liquification of a gas depends on their intermolecular force of attraction which in turn is measured in terms of van der Waals’ constant ‘a’. Hence, higher the value of ‘a’, greater the intermolecular force of attraction, easier the liquification. In the present case, NH3 has highest ‘a’, can most easily be liquefied.
ease of liquification is directly proportional to ‘a’.If the value of ‘a’ is more then if we apply even less pressure also the gas can be liquified,so in order to liquify easily we should have more ‘a’. so more ‘a’ =more easily liqification.
As NH3 has higher *a value, it can be easily liquifiable. Such that [rate of liquification is directly proportional to a value]
Thanks, hope it helps.
Profile image of Yash Chourasiya
6 Years ago
Dear Student

Option (C) NH3is Correct.

BecauseThe ease of liquification of a gas depends on their intermolecular force of attraction which in turn is measured in terms of van der Waals’ constant ‘a’. Hence, higher the value of ‘a’, greater the intermolecular force of attraction, easier the liquification.

I hope this answer will help you.
Thanks & Regards
Yash Chourasiya