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Grade: 11

                        

The reaction A+B=C+D is studied in a one litre vessel at 250 degree celcius. The initial concentration of A was 3n and that of B was n. when eqilibrium was attained, equilibrium concentration of C was found to the equal to the equilibrium concentration of B. What is the concentration of D at equilibrium ?

3 years ago

Answers : (2)

Riddhi Jain
28 Points
							A     +        B         =  C   +  D3n             n              0       0       at t=03n-x         n-x            x      x       at t=t`Since moles of B is equal to C at equilibriumTherefore,  n-x=x                    So,x=n/2  A         +       B     =    C  +  D        3n-n/2     n-n/2        n/2   n/2Hence, D= n/2
						
3 years ago
ankit singh
askIITians Faculty
596 Points
							
The concentration of d at equilibrium will be n / 2.
Option (A) is correct.
Explanation:
The initial concentrations of the reactants are given below.
                             A   +     B   ⇄      C    +     D
At time "t" = 0    3n          n            0            0
At time "t" = 0    3n - x     n - x       x             x
n − x = x → x = n / 2
i.e. [D] equation  =n / 2
Thus the concentration of d at equilibrium will be n / 2.
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