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The reaction A+B=C+D is studied in a one litre vessel at 250 degree celcius. The initial concentration of A was 3n and that of B was n. when eqilibrium was attained, equilibrium concentration of C was found to the equal to the equilibrium concentration of B. What is the concentration of D at equilibrium ?

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3 years ago

```							A     +        B         =  C   +  D3n             n              0       0       at t=03n-x         n-x            x      x       at t=t`Since moles of B is equal to C at equilibriumTherefore,  n-x=x                    So,x=n/2  A         +       B     =    C  +  D        3n-n/2     n-n/2        n/2   n/2Hence, D= n/2
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3 years ago
```							The concentration of d at equilibrium will be n / 2.Option (A) is correct.Explanation:The initial concentrations of the reactants are given below.                             A   +     B   ⇄      C    +     DAt time "t" = 0    3n          n            0            0At time "t" = 0    3n - x     n - x       x             xn − x = x → x = n / 2i.e. [D] equation  =n / 2Thus the concentration of d at equilibrium will be n / 2.Also learn moreWhat is the equilibrium concentration of each of the substances in the equilibrium when the initial concentration of ICl was 0.78 M?2 ICl(g)⇌I2(g) + Cl2(g) ; KC = 0.14
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2 months ago
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