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The normality of 10 mL of a ‘20V’ H 2 O 2 solution is? [AC ch5 pg 31 Q34]

The normality of 10 mL of a ‘20V’ H2O2 solution is?
 
 
 
[AC ch5 pg 31 Q34]

Grade:12th pass

3 Answers

Naveen Kumar
askIITians Faculty 60 Points
9 years ago
20VH2O2 means that 1 litre of H2O2 solution would produce 20 litre of Oxygen.

2H2O2.....................>H2O+ O2

From the equation it is clear that 2 moles of H2O2 produce 1 mol of O2
But 20V H2O2 will produce 20 litre of oxygen for 1 litre of H2O2.
............................................⇒ (20litre/24.4litre) mol of oxygen liberated for 1 litre of H2O2
So in 1 litre solution of H2O2, moles of H2O2=2*moles of oxygen = (2*20/24.4) mol/litre=1.67M
n-factor of H2O2=2
So, normality=Molarity*n-factor=1.67*2=3.34N

Kushagra Madhukar
askIITians Faculty 628 Points
3 years ago
Dear student,
Please find the attached solution to your problem below.
 
20V H2O2 means that 1 litre of H2O2 solution would produce 20 litre of Oxygen.
2H2O2 → H2O + O2
From the equation it is clear that 2 moles of H2O2 produce 1 mol of O2
But 20V H2O2 will produce 20 litre of oxygen for 1 litre of H2O2.
⇒ (20litre/24.4litre) mol of oxygen liberated for 1 litre of H2O2
So in 1 litre solution of H2O2, moles of H2O2 = 2*moles of oxygen = (2*20/24.4) mol/litre = 1.67M
n-factor of H2O2 = 2
So, normality = Molarity*n-factor = 1.67*2 = 3.34N
 
Hope it helps.
Thanks and regards,
Kushagra
Yash
13 Points
one year ago
20V H2O2 means that 1 litre of H2O2 solution would produce 20 litre of Oxygen.
 
2H2O2 → H2O + O2
 
From the equation it is clear that 2 moles of H2O2 produce 1 mol of O2
 
But 20V H2O2 will produce 20 litre of oxygen for 1 litre of H2O2.
 
⇒ (20litre/24.4litre) mol of oxygen liberated for 1 litre of H2O2
 
So in 1 litre solution of H2O2, moles of H2O2 = 2*moles of oxygen = (2*20/22.4) mol/litre = 1.785M
 
n-factor of H2O2 = 2
 
So, normality = Molarity*n-factor = 1.79*2 = 3.58N
 
 

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