MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12
        The normal boiling point of water is 373 Kelvin.vapour pressure of water at 298 kelvin is 23 mm .if enthalpy of vaporization is 40.656 kg per mole the boiling point of water at 23 mm pressure will be
one year ago

Answers : (1)

Arun
23357 Points
							
 
From the Calsius Clapeyron formulae:
P = A exp (- DHvap / R T)
P = 23exp(-40656/8.3145*(298 – 373)) = 23exp(65.19) K 
 
 
Regards
Arun (askIITians forum expert)
one year ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 141 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details