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Grade 12Physical Chemistry

The normal boiling point of water is 373 Kelvin.vapour pressure of water at 298 kelvin is 23 mm .if enthalpy of vaporization is 40.656 kg per mole the boiling point of water at 23 mm pressure will be

Profile image of Geetha
8 Years agoGrade 12
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1 Answer

Profile image of Arun
8 Years ago
 
From the Calsius Clapeyron formulae:
P = A exp (- DHvap / R T)
P = 23exp(-40656/8.3145*(298 – 373)) = 23exp(65.19) K 
 
 
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Arun (askIITians forum expert)