Grade 12Physical Chemistry
The mass of 70 percent pure H2SO4 required for neutralisation of 1 mol of NaOH -A 49 gB 98gC 70gD 34.3g
The mass of 70 percent pure H2SO4 required for neutralisation of 1 mol of NaOH -
A 49 g
B 98g
C 70g
D 34.3g
1 Answer
Arun
Dear Ayush
If we take into context the neutralization reaction
Then:
h2so4 + 2NaOH ---> Na2SO4 + 2H2O
0.5 Moles of h2so4 are needed
And we know that the molar mass of h2so4 = 98g
0.5 moles mass of h2so4 would be = 98*0.5=49g
70 g h2so4 is there in 100 g solution (70% h2so4)
Thus 49g is there in 70g of solution
(49x100)/70=70g
Ans = 70 g
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