Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Relationship b/w relative lowering of vapour pressure and molality
Relative lowering of vapour pressure is one of the colligative properties.Colligative properties are those properties of solutions which depend only on the number of solute particles and independent of the nature of the solute particles. Relative lowering of vapour pressure is the ratio of lowering of vapour pressure to the vapour pressure of pure solvent.It is given as-- p0 – p / p0 = xBwhere, p0 = Vapour pressure of pure solvent p = Vapour pressure of solution containing non-volatile solute xB = mole fraction of soluteNow this Relative lowering of vapour pressure is related to the molality of solution by the following mathematical expression-- p0 – p / p0 = m * MA / 1000where, m = molality of solution and MA = molar mass of the solvent
LVP: This difference between the vapour pressure of pute solvent (p°) and the vapour pressure of the solution (ps) is known as lowering of vapour pressure (LVP)Mathematically,delta p=p°-psRLVP: The ratio of lowering of vapour pressure (delta p) to the vapour pressure of pure solvent (p°)is called relative lowering of vapour pressure (RLVP)According to raoult`s law, RLVP=XB (mole fraction of solute) =》p°-ps a W --------- = --- × ---- P° M bFrom this equation, we can find molar weight of solute (M).
1000/M(P-p/p)=mm=molalityM=molar massP=vapour pressure of solutionp= vapour pressure of pure solvent
Dear Student,Please find below the solution to your problem.Relative lowering of vapour pressure is one of the colligative properties.Colligative properties are those properties of solutions which depend only on the number of solute particles and independent of the nature of the solute particles.Relative lowering of vapour pressure is the ratio of lowering of vapour pressure to the vapour pressure of pure solvent.It is given as--(p0 – p) / p0 = xBwhere, p0 = Vapour pressure of pure solventp = Vapour pressure of solution containing non-volatile solutexB = mole fraction of soluteNow this Relative lowering of vapour pressure is related to the molality of solution by the following mathematical expression--(p0 – p) / p0 = m * MA / 1000where, m = molality of solutionand MA = molar mass of the solventThanks and Regards
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -