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One litre of N/2 HCl solution is heated in a beaker.it was observed that when the volume of solution was reduced to 600 ml, 3.25 g HCl in lost . Calculate the normality of the new solution .
From the N1V1 = constant concept we get,1*1/2 = 0.6*N2we get,N2 = 10/12 => 5/6 => 0.83This would be the final normality of the solution.
1L of N/2 HCL contains = ½ x 36.5 = 18.25g HCL now present = 18.5-3.25 = 15.25 which is approximately =15gNow, volume=600 ml= 0.600 LNow Normality= 15/36.5 x 1/0.600 = 0.68N Therefore the Normality is equal to 1.68 N
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