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Integrated rate law for a zero order reaction is :
[R]=-kt +[R]0
When we compare the equation with the equation of a straight line i.e. y = mx + c,
we get slope of line = m = -k and Y intercept = [R]0
Slope is equal to –k for the plot [R] vs t
Same equation can also be written as
t = 1/k([Ro]-[R])
When compared with the equation of straight line y = mx + c
The slope would be 1/k for the plot t vs ([Ro]-[R]) and the y intercept would be 0 as c = 0
Hope it’s clear to you.
Thanks & Regards
Pankaj Singh
askIITians Faculty
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