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Grade: 12th pass

                        

In acidic medium, equivalent weight of K 2 Cr 2 O 7 (Molar weight= M) is M/3 M/4 M/6 M/2 Do explain your answer.

one year ago

Answers : (3)

Rachna Verma
15 Points
							
The correct answer is M/3 because the oxidation state of Cr changes from 6 to 3 in presence of acidic medium
one year ago
Vikas TU
13786 Points
							
K2Cr2O7 in solution gives following ions -
K2Cr2O7 + 14H+ + 6e- → 2K+ + 2Cr3+ + 7H2O
 
Here, 6 e- participate in the reaction, hence chemical equivalent is 6.
 
Equivalent weight is calculated by -
Z = W / E
Z = 294 / 6
=> M/6 
 
one year ago
Arun
25141 Points
							
 

molecular weight of pottasium dichromate = M , X factor in acidic medium  = 6

equivalent weight = molecular weight / X factor 

                         = M /6 (option C)

one year ago
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