if |z1| = |z2| and arg(z1/z2) = pi then z1+z2 is equal to
a) 0
b) Purely Imaginary
c) Purely Real
d) None
[Ans. a) 0]

Question

if |z1| = |z2| and arg(z1/z2) = pi then z1+z2 is equal to a) 0 b) Purely Imaginary c) Purely Real d) None [Ans. a) 0]

Arun · Answer

Let |z1| = |z2| = r , and arg(z2) = A Given, arg(z1) - arg(z2) = π arg(z1) = π + arg(z2) arg(z1) = π + A So, z2 = r cos(A) + i sin(A) z1 = r cos(π + A) + i sin(π + A) z1 = - [r cos(A) + i sin (A)] z1 = - z2 z1 + z2 = 0.

chumtiya · Answer

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if |z1| = |z2| and arg(z1/z2) = pi then z1+z2 is equal to a) 0 b) Purely Imaginary c) Purely Real d) None [Ans. a) 0]

if |z1| = |z2| and arg(z1/z2) = pi then z1+z2 is equal to
a) 0
b) Purely Imaginary
c) Purely Real
d) None
[Ans. a) 0]

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if |z1| = |z2| and arg(z1/z2) = pi then z1+z2 is equal to a) 0 b) Purely Imaginary c) Purely Real d) None [Ans. a) 0]

if |z1| = |z2| and arg(z1/z2) = pi then z1+z2 is equal toa) 0b) Purely Imaginaryc) Purely Reald) None[Ans. a) 0]

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if |z1| = |z2| and arg(z1/z2) = pi then z1+z2 is equal to
a) 0
b) Purely Imaginary
c) Purely Real
d) None
[Ans. a) 0]