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Physical Chemistry

If the de-Broglie wavelength of the fourth Bohr orbit of hydrogen atom is 4A, the circumference of the orbit will be-

Profile image of Tanusri Bose
8 Years agoGrade
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1 Answer

Profile image of Arun
8 Years ago
Use mvr=nh/2π

=> mvr=nh/2π
=> 2πr=nh/mv
=> 2πr=n×lambda {lambda=h/mv}

now, n=4 and wavelength=4A

=> 2πr(circumference) = 4×4
= 16A