if Na+ are placed at fcc lattice point and Cl- are placed at all O.H.V. then what will be the structure with respect to Cl-

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Vikas TU · Answer

The contribution of Na+ is: Na+ = 8*1/8 + 1*6/2 = > 3 + 1 => 4 The contribution of Cl- is: Cl- = 1*6/2 = 3 Therefore the formulae is=> Na4Cl3

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if Na+ are placed at fcc lattice point and Cl- are placed at all O.H.V. then what will be the structure with respect to Cl-

if Na+ are placed at fcc lattice point and Cl- are placed at all O.H.V. then what will be the structure with respect to Cl-

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if Na+ are placed at fcc lattice point and Cl- are placed at all O.H.V. then what will be the structure with respect to Cl-

if Na+ are placed at fcc lattice point and Cl- are placed at all O.H.V. then what will be the structure with respect to Cl-

1 Answers

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