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if Cu2+/Cu electrode is diluted 100 times ,then the change in emf is. a- increase of 59 mV b-decreae of 59 mV c-inc of 29.5 mV d- dec of 29.5mV

if Cu2+/Cu electrode is diluted 100 times ,then the change in emf is.
a- increase of 59 mV
b-decreae of 59 mV
c-inc of 29.5 mV
d- dec of 29.5mV

Grade:12

2 Answers

Yash Jain
55 Points
9 years ago
It must be B.
See, by the Nearnst equation at 25oC, we have
 Ecell = Eocell  - 0.05916V/z*log(Aox/Ared)
As Cu2+ is reductant and its conc. is getting reduced by 100 times, so the log value will increase by the factor of 2. Also the value of z is 2.
Thus, the overall E will decrease by 59mV
 
ankit singh
askIITians Faculty 614 Points
3 years ago
s Cu 2+ is reductant and its conc. is getting reduced by 100 times, so the log value will increase by the factor of 2.
thank u
regards ankit singh

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